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wabbit  
#1 Posted : Monday, July 25, 2005 2:06:14 AM(UTC)
wabbit

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I was having a think about a completely different problem, then procrastinated, and stumbled in this problem: What is the most number of ways to achieve a MS function without using the function itself? What function can be duplicated in the most ways? My first thought was the Cross() function... Instead of: x:=Mov(C,21,S); y:=Mov(C,55,S); Cross(x,y) we can write: [list:aa8ba5a32a] [*:aa8ba5a32a]x:=Mov(C,21,S); y:=Mov(C,55,S); x>y and Ref(x<=y,-1); [*:aa8ba5a32a]x:=Mov(C,21,S); y:=Mov(C,55,S); z:=x>y; z and ref(z=0,-1); {really similar to the one above, but isnt that what we are proving?} [*:aa8ba5a32a]x:=Mov(C,21,S); y:=Mov(C,55,S); z:=x>y; z and alert(z=0,2); [*:aa8ba5a32a]x:=Mov(C,21,S); y:=Mov(C,55,S); z:=x>y; Sum(z,2)=1 {works in either direction!} [/list:u:aa8ba5a32a] Anyone got any more? Maybe another function? Lets have some fun! \\:D/ wabbit :D
Patrick  
#2 Posted : Monday, July 25, 2005 2:36:59 AM(UTC)
Patrick

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x:=Mov(C,21,S)-Mov(C,55,S); Sum(x,2)=1 ... Interresting :D
wabbit  
#3 Posted : Monday, July 25, 2005 4:11:04 AM(UTC)
wabbit

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I had an epiphany / epifony / apiffany/ idea this morning.... :lol: wabbit :D P.S. Epiphony.
Patrick  
#4 Posted : Monday, July 25, 2005 4:13:13 AM(UTC)
Patrick

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:lol: :lol: No it's good, it will demistify some of the indicators out there ...
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