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 ketal #1 Posted : Wednesday, March 29, 2017 5:32:58 AM(UTC) Rank: MemberGroups: Registered, Registered Users, Unverified UsersJoined: 3/7/2014(UTC)Posts: 17Thanks: 6 times Hi, I am trying to code for bar highlight for pivot on the basis of the close. following are the conditions a) Low pivot (LP) 1) LP must close lower than previous 2 bars close ie close of bar -1 and close of bar -2. the two closes do not have to be in consecutive order. I have coded- C>REF(C,-1) AND C>REF(C,-2) 2) bar +1 close must be equal or > LP close I have coded- C>=REF(C,1) 3) LP is confirmed as LP bar(s) next to +1 bar closes equal to of > +1 bar close. it may be +2 bar or +3 bar or any bar as long as there is no close below LP bar close as its void the sequence.  Here I am not able to do the code- please help me.  for High Pivot (HP) reverse the conditions. Regards, K
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 wabbit #2 Posted : Wednesday, March 29, 2017 1:58:41 PM(UTC) Rank: Advanced MemberGroups: Registered, Registered Users, Subscribers, Unverified UsersJoined: 10/28/2004(UTC)Posts: 3,111Location: Perth, Western AustraliaWas thanked: 16 time(s) in 16 post(s) It's late, I'm tired, your code doesn't match your words, so here goes.... Code:`````` lpBarPlus1:= Ref(C,-1) < Ref(C,-2) AND Ref(C,-1) < Ref(C,-3) AND Ref(C,-1) <=C; lpBarPlus1Close:=ValueWhen(1,lpBarPlus1,C); count:=Cum(C>lpBarPlus1Close); counter:=count-ValueWhen(1,lpBarPlus1,count); confirmation:=counter=1 AND Alert(counter<>1,2); {plot} confirmation; `````` Edited by user Thursday, April 20, 2017 8:47:45 AM(UTC)  | Reason: Fixed code tags 1 user thanked wabbit for this useful post. ketal on 4/3/2017(UTC)
 ketal #3 Posted : Monday, April 3, 2017 8:17:37 AM(UTC) Rank: MemberGroups: Registered, Registered Users, Unverified UsersJoined: 3/7/2014(UTC)Posts: 17Thanks: 6 times Hi, I am sorry not able to make my self understand properly. The above code is not the one I am looking for. I have made the semantics for both high pivot and low pivot. Kindly look at it and plz help. http://i.imgur.com/T0O24jW.png http://i.imgur.com/954Qspo.png
 wabbit #4 Posted : Monday, April 3, 2017 4:35:38 PM(UTC) Rank: Advanced MemberGroups: Registered, Registered Users, Subscribers, Unverified UsersJoined: 10/28/2004(UTC)Posts: 3,111Location: Perth, Western AustraliaWas thanked: 16 time(s) in 16 post(s) Because you could have multiple instances where the LP condition is true whilst awaiting confirmation, the only real solution is leave the limited metastock formula language behind and use an external function written in a far more powerful language. 1 user thanked wabbit for this useful post. ketal on 4/3/2017(UTC)
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