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Groups: Registered, Registered Users, Subscribers Joined: 7/25/2007(UTC) Posts: 2
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Rank: Advanced Member
Groups: Registered, Registered Users, Subscribers, Unverified Users Joined: 10/28/2004(UTC) Posts: 3,111 Location: Perth, Western Australia
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Marcus, In this instance, more important than how its being done is what is being done. Look very carefully and all you will see is that Ed has created an Exponential Moving Average. The length of the EMA is (2*N)-1. In his example on the web page you linked us to he used 5-days, so (2*5)-1 = 9. You achieve the same results using: Hope this helps. wabbit [:D]
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Rank: Newbie
Groups: Registered, Registered Users, Subscribers Joined: 7/25/2007(UTC) Posts: 2
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Hmm... now I understand... Thank you wabbit!!!! [:D]
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