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konrad  
#1 Posted : 19 years ago
konrad

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if(c,12,s)> (C,15,S)( -1,0) ROC( c,15,S)< ROC( C,20,S) (-1,0) if it is , or if its not, how this influence in graph? how I can check if this is true or is false , where I can see this on graph?Why is require to write (-1,0)?
StorkBite  
#2 Posted : 19 years ago
StorkBite

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What is the -1,0 supposed to represent?
konrad  
#3 Posted : 19 years ago
konrad

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Here is more explanation: I have read a formula primer and stay on page 17. Logical Being If (Condition, True Result, False result) If the 12 period RSi is above 70 or the close has dropped by 5 percent or more over the last 3 periods, plot 1, otherwise plot a 0 If ((RSI (12) > 70) OR (((C-Ref(C,3)) Ref (C,-3)) *100<5), 1,0 and here is my question: Why Should I write 1,0 and what that represent? I know that represent 1 for true 0 for false, but how this influence in graph? where I can see that in chart? Is that require to write (1,0) or Metastock Language will do this for me? Can you show me example with graph I am sorry but I can't understand this part of formula and I don't want to stop learning please help me out here!
StorkBite  
#4 Posted : 19 years ago
StorkBite

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Well... in this case the result of a true condition = 1 which means to plot the value 1. The result of a false condition = 0 which means to plot the value 0. Basically you have a flip-flop... on or off condition. Some examples: if (mov(c,12,s) > mov(C,15,S), 1, 0); if (ROC(c,15,S) < ROC( C,20,S), 1, 0); if (RSI(12) > 70 OR (c - ref (c,-3)) < 5, 1, 0); <<< I didn't understand your reference to this one, so it's not right
konrad  
#5 Posted : 19 years ago
konrad

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If((C>Mov(C,40,S)) AND (C>Mov(C,120,S)),1,0) I use this formula above to see how this work and the (1,0) represtent true of false of that statement right? is that correct? the high point represtent 1 true, the low point represtent 0 low
StorkBite  
#6 Posted : 19 years ago
StorkBite

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If(C > Mov(C,40,S) AND C > Mov(C,120,S), 1, 0); This will plot a 1 if C is greater than the 40 period average AND the 120 period average. I think what you're thinking is true... the low point on the graph (zero) means that your condition is false; the high point on the graph (one) means that your condition is true.
konrad  
#7 Posted : 19 years ago
konrad

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Thank you G.Stockman :)
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